(4x^2-2x+7)/(x-1)

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Solution for (4x^2-2x+7)/(x-1) equation:


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(4*x^2-(2*x)+7)/(x-1) = 0

(4*x^2-2*x+7)/(x-1) = 0

4*x^2-2*x+7 = 0

4*x^2-2*x+7 = 0

DELTA = (-2)^2-(4*4*7)

DELTA = -108

DELTA < 0

1 = 0

1/(x-1) = 0

x belongs to the empty set

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